Given a list of integers, determine whether the sum of its elements is odd or even. Give your answer as a string matching "odd" or "even".
My code:
function oddOrEven(array) {
let result = 0
for(let i = 0; i < array.length; i++) {
result += array[i]
}
if(result % 2 === 0) {
return 'even'
} else {
return 'odd'
}
}
function oddOrEven(arr) {
return arr.reduce((a,b)=>a+b,0) % 2 ? 'odd' : 'even';
}